SOLVED: Hints: 1. Block 224.151.60.176/28 utilizes a subnet mask of 28 bits (/28 in the CIDR address): 2. This means your subnet mask will use the first 28 bits as in: 11111111.11111111.11111111.11110000 (
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SOLVED: Consider the IP address 128.119.40.0/28,and answer the following questions: .What is the subnet mask? How many subnets does the subnet mask (calculated in the previous stepprovide What is the block size
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